How to perform rendering a model in the Django Admin interface?

The following article describes How to perform rendering a model in the Django Admin interface with an example.

To render a model in the Django Admin interface, you can create an Admin class for the model and register it with the admin site. Here’s an example of how to do this for a complaint-tracking system.

  1. Define your model in
from django.db import models

class Complaint(models.Model):
    my_name = models.CharField(max_length=250)
    description = models.TextField()
    date_filed = models.DateTimeField(auto_now_add=True)
    resolved = models.BooleanField(default=False)

    def __str__(self):
        return self.my_name
  1. Create an Admin class for your model in
from django.contrib import admin
from .models import Complaint

class ComplaintAdmin(admin.ModelAdmin):
    list_display = ('my_name', 'date_filed', 'resolved')
    list_filter = ('resolved',)
    search_fields = ('My_name', 'description'), ComplaintAdmin)

In the above code, ComplaintAdmin is an admin class for the Complaint model. The list_display attribute specifies the fields to display in the admin list view, list_filter specifies the filters to include on the right-hand side of the list view, and search_fields specifies the fields to search when using the search box.

  1. Access the admin interface

Navigate to http://localhost:8000/admin. Once logged in, you’ll be able to view, add, edit and delete Complaints.

Note: You will need to make sure that your app is included in your project’s INSTALLED_APPS setting.

That’s it! You now have a Django Admin interface for your Complaint model.

Further Reading

Introduction to Django Framework and its Features

Django Practice Exercise

Examples of Array Functions in PHP

Basic Programs in PHP

Registration Form Using PDO in PHP

Inserting Information from Multiple CheckBox Selection in a Database Table in PHP


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