20 Simple and Compound Interest Questions with Answers and Solutions
20 Simple and Compound Interest Questions with Answers and Solutions
Simple Interest and Compound Interest are important topics in quantitative aptitude and are commonly asked in placement tests, competitive examinations, recruitment assessments, banking examinations, and entrance tests. These questions test your understanding of principal, rate of interest, time, amount, annual compounding, and the difference between simple and compound interest.
This practice set contains 20 original Simple and Compound Interest questions with detailed answers and step-by-step solutions. The questions begin with basic interest calculations and gradually move toward finding principal, rate, time, compound amount, and comparisons between simple and compound interest.
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Try to solve all 20 questions before checking the answers.
Detailed answers and solutions are provided after Question 20.
Simple and Compound Interest Aptitude Test
Question 1
What is the simple interest on ₹5,000 at 8% per annum for 3 years?
A. ₹1,000
B. ₹1,100
C. ₹1,200
D. ₹1,400
Question 2
Find the amount on ₹8,000 invested at 6% simple interest per annum for 2 years.
A. ₹8,860
B. ₹8,960
C. ₹9,000
D. ₹9,200
Question 3
A sum of ₹6,000 earns ₹1,440 as simple interest in 4 years. What is the annual rate of interest?
A. 5%
B. 6%
C. 7%
D. 8%
Question 4
At 10% simple interest per annum, how long will ₹4,500 take to earn ₹1,350 as interest?
A. 2 years
B. 2.5 years
C. 3 years
D. 4 years
Question 5
A sum earns ₹2,100 as simple interest at 7% per annum in 5 years. What is the principal?
A. ₹5,000
B. ₹5,500
C. ₹6,000
D. ₹6,500
Question 6
What is the compound amount on ₹10,000 at 10% per annum for 2 years, compounded annually?
A. ₹11,800
B. ₹12,000
C. ₹12,100
D. ₹12,200
Question 7
What is the compound interest on ₹8,000 at 5% per annum for 2 years, compounded annually?
A. ₹800
B. ₹820
C. ₹840
D. ₹860
Question 8
Juhi invests ₹12,000 at 10% per annum compounded annually. What will be the amount after 3 years?
A. ₹15,720
B. ₹15,840
C. ₹15,972
D. ₹16,000
Question 9
What is the difference between compound interest and simple interest on ₹10,000 at 10% per annum for 2 years?
A. ₹80
B. ₹100
C. ₹120
D. ₹200
Question 10
A sum becomes ₹14,520 in 2 years at 10% compound interest per annum. What was the original principal?
A. ₹11,000
B. ₹11,500
C. ₹12,000
D. ₹12,500
Question 11
A sum doubles itself in 10 years at simple interest. What is the annual rate of interest?
A. 8%
B. 10%
C. 12%
D. 15%
Question 12
At what annual simple interest rate will ₹7,500 amount to ₹9,300 in 4 years?
A. 5%
B. 6%
C. 7%
D. 8%
Question 13
What is the compound interest on ₹20,000 at 8% per annum for 2 years, compounded annually?
A. ₹3,200
B. ₹3,280
C. ₹3,328
D. ₹3,400
Question 14
Cherry invests ₹15,000 at 12% simple interest per annum for 2 years. Charlie invests the same amount at 10% compound interest per annum for 2 years. Who earns more interest and by how much?
A. Cherry by ₹450
B. Cherry by ₹600
C. Charlie by ₹450
D. Charlie by ₹600
Question 15
A principal of ₹25,000 earns compound interest at 20% per annum for 2 years. What is the final amount?
A. ₹35,000
B. ₹35,500
C. ₹36,000
D. ₹36,500
Question 16
The compound amount on a sum after 2 years at 10% per annum is ₹24,200. What is the principal?
A. ₹18,000
B. ₹20,000
C. ₹22,000
D. ₹22,500
Question 17
A sum amounts to ₹13,310 after 3 years at 10% compound interest per annum. What was the principal?
A. ₹9,000
B. ₹10,000
C. ₹10,500
D. ₹11,000
Question 18
What is the difference between compound interest and simple interest on ₹20,000 for 2 years at 5% per annum?
A. ₹40
B. ₹50
C. ₹75
D. ₹100
Question 19
A sum earns ₹3,600 simple interest in 3 years at 8% per annum. If the same principal is invested for 2 years at 10% compound interest per annum, what compound interest will it earn?
A. ₹2,800
B. ₹3,000
C. ₹3,150
D. ₹3,200
Question 20
Nyra invests ₹20,000 for 2 years. One scheme offers 12% simple interest per annum, while another offers 12% compound interest per annum compounded annually. How much more will she earn under the compound-interest scheme?
A. ₹240
B. ₹288
C. ₹320
D. ₹360
Answers and Detailed Solutions
Answer 1: C — ₹1,200
Simple Interest is calculated using:
[
SI=\frac{P\times R\times T}{100}
]
Here:
[
P=5000,\quad R=8,\quad T=3
]
Therefore:
[
SI=\frac{5000\times8\times3}{100}
]
[
=1200
]
Therefore:
Correct Answer: ₹1,200
Answer 2: B — ₹8,960
Principal:
[
P=8000
]
Rate:
[
R=6%
]
Time:
[
T=2
]
Simple Interest:
[
SI=\frac{8000\times6\times2}{100}
]
[
=960
]
Amount:
[
A=P+SI
]
[
=8000+960
]
[
=8960
]
Therefore:
Correct Answer: ₹8,960
Answer 3: B — 6%
Given:
[
SI=1440
]
[
P=6000
]
[
T=4
]
Using:
[
SI=\frac{PRT}{100}
]
Therefore:
[
1440=\frac{6000\times R\times4}{100}
]
So:
[
R=\frac{1440\times100}{6000\times4}
]
[
=6%
]
Therefore:
Correct Answer: 6%
Answer 4: C — 3 years
Given:
[
P=4500
]
[
R=10%
]
[
SI=1350
]
Using:
[
T=\frac{SI\times100}{P\times R}
]
Therefore:
[
T=
\frac{1350\times100}{4500\times10}
]
[
=3
]
Therefore:
Correct Answer: 3 years
Answer 5: C — ₹6,000
Given:
[
SI=2100
]
[
R=7%
]
[
T=5
]
Using:
[
P=\frac{SI\times100}{R\times T}
]
Therefore:
[
P=
\frac{2100\times100}{7\times5}
]
[
=\frac{210000}{35}
]
[
=6000
]
Therefore:
Correct Answer: ₹6,000
Answer 6: C — ₹12,100
For compound interest:
[
A=P\left(1+\frac{R}{100}\right)^T
]
Here:
[
P=10000
]
[
R=10
]
[
T=2
]
Therefore:
[
A=
10000(1.10)^2
]
[
=10000\times1.21
]
[
=12100
]
Therefore:
Correct Answer: ₹12,100
Answer 7: B — ₹820
Principal:
[
8000
]
Rate:
[
5%
]
After the first year:
[
8000\times1.05=8400
]
After the second year:
[
8400\times1.05=8820
]
Compound Interest:
[
8820-8000=820
]
Therefore:
Correct Answer: ₹820
Answer 8: C — ₹15,972
Principal:
[
12000
]
Rate:
[
10%
]
Time:
3 years.
Amount:
[
A=12000(1.10)^3
]
[
=12000\times1.331
]
[
=15972
]
Therefore:
Correct Answer: ₹15,972
Answer 9: B — ₹100
Simple Interest:
[
SI=\frac{10000\times10\times2}{100}
]
[
=2000
]
Compound Amount:
[
10000(1.10)^2
]
[
=12100
]
Compound Interest:
[
12100-10000
]
[
=2100
]
Difference:
[
2100-2000
]
[
=100
]
Therefore:
Correct Answer: ₹100
Answer 10: C — ₹12,000
Given compound amount:
[
A=14520
]
Rate:
10%
Time:
2 years.
Using:
[
A=P(1.10)^2
]
Therefore:
[
14520=1.21P
]
[
P=\frac{14520}{1.21}
]
[
=12000
]
Therefore:
Correct Answer: ₹12,000
Answer 11: B — 10%
If a sum doubles, the interest earned equals the original principal.
Assume principal:
[
P
]
After 10 years, amount:
[
2P
]
Therefore:
[
SI=P
]
Using:
[
SI=\frac{PRT}{100}
]
[
P=\frac{P\times R\times10}{100}
]
Cancel (P):
[
1=\frac{10R}{100}
]
Therefore:
[
R=10%
]
Correct Answer: 10%
Answer 12: B — 6%
Principal:
[
7500
]
Amount:
[
9300
]
Therefore Simple Interest:
[
9300-7500=1800
]
Time:
4 years.
Using:
[
R=\frac{SI\times100}{P\times T}
]
[
R=
\frac{1800\times100}{7500\times4}
]
[
=6%
]
Therefore:
Correct Answer: 6%
Answer 13: C — ₹3,328
Principal:
[
20000
]
Rate:
8%
Time:
2 years.
Amount:
[
A=20000(1.08)^2
]
[
=20000\times1.1664
]
[
=23328
]
Compound Interest:
[
23328-20000
]
[
=3328
]
Therefore:
Correct Answer: ₹3,328
Answer 14: A — Cherry by ₹450
Cherry’s Simple Interest
Principal:
₹15,000
Rate:
12%
Time:
2 years.
[
SI=
\frac{15000\times12\times2}{100}
]
[
=3600
]
Charlie’s Compound Interest
[
A=15000(1.10)^2
]
[
=15000\times1.21
]
[
=18150
]
Compound Interest:
[
18150-15000=3150
]
Difference:
[
3600-3150
]
[
=450
]
Therefore, Cherry earns:
₹450 more
Correct Answer:
Cherry by ₹450
Answer 15: C — ₹36,000
Principal:
[
25000
]
Rate:
20%
Time:
2 years.
[
A=25000(1.20)^2
]
[
=25000\times1.44
]
[
=36000
]
Therefore:
Correct Answer: ₹36,000
Answer 16: B — ₹20,000
Amount:
[
24200
]
Rate:
10%
Time:
2 years.
[
24200=P(1.10)^2
]
[
24200=1.21P
]
Therefore:
[
P=\frac{24200}{1.21}
]
[
=20000
]
Therefore:
Correct Answer: ₹20,000
Answer 17: B — ₹10,000
Amount:
[
13310
]
Rate:
10%
Time:
3 years.
Using:
[
A=P(1.10)^3
]
Since:
[
(1.10)^3=1.331
]
Therefore:
[
13310=1.331P
]
[
P=\frac{13310}{1.331}
]
[
=10000
]
Therefore:
Correct Answer: ₹10,000
Answer 18: B — ₹50
For two years, the difference between compound interest and simple interest can also be calculated as:
[
P\left(\frac{R}{100}\right)^2
]
Given:
[
P=20000
]
[
R=5
]
Therefore:
[
Difference
20000\left(\frac{5}{100}\right)^2
]
[
=20000\times0.0025
]
[
=50
]
Therefore:
Correct Answer: ₹50
We can also verify this directly.
Simple Interest:
[
\frac{20000\times5\times2}{100}
2000
]
Compound Amount:
[
20000(1.05)^2
22050
]
Compound Interest:
[
22050-20000=2050
]
Difference:
[
2050-2000=50
]
Answer 19: C — ₹3,150
First find the principal.
Given:
[
SI=3600
]
[
T=3
]
[
R=8
]
Using:
[
P=\frac{SI\times100}{R\times T}
]
[
P=
\frac{3600\times100}{8\times3}
]
[
=\frac{360000}{24}
]
[
=15000
]
Now invest ₹15,000 for 2 years at 10% compound interest.
Amount:
[
A=15000(1.10)^2
]
[
=18150
]
Compound Interest:
[
18150-15000
]
[
=3150
]
Therefore:
Correct Answer: ₹3,150
Answer 20: B — ₹288
Principal:
[
₹20000
]
Rate:
12%
Time:
2 years.
Simple Interest
[
SI=
\frac{20000\times12\times2}{100}
]
[
=4800
]
Compound Interest
[
A=
20000(1.12)^2
]
[
=20000\times1.2544
]
[
=25088
]
Compound Interest:
[
25088-20000
]
[
=5088
]
Difference:
[
5088-4800
]
[
=288
]
Therefore:
Correct Answer: ₹288
Quick Answer Key
| Question | Answer | Question | Answer |
|---|---|---|---|
| 1 | C | 11 | B |
| 2 | B | 12 | B |
| 3 | B | 13 | C |
| 4 | C | 14 | A |
| 5 | C | 15 | C |
| 6 | C | 16 | B |
| 7 | B | 17 | B |
| 8 | C | 18 | B |
| 9 | B | 19 | C |
| 10 | C | 20 | B |
How Did You Score?
| Correct Answers | Performance |
|---|---|
| 18–20 | Excellent — You have a strong understanding of Simple and Compound Interest. |
| 15–17 | Very Good — Your fundamentals are strong; practice reverse principal and comparison questions. |
| 11–14 | Good — Review compound amount, rate, and difference calculations. |
| 6–10 | Needs Practice — Revise the basic SI and CI formulas and attempt the test again. |
| 0–5 | Beginner — Start with principal, rate, time, simple interest, and amount before moving to compound interest. |
Important Simple Interest Formulas
Simple Interest
[
SI=
\frac{P\times R\times T}{100}
]
where:
- (P) = Principal
- (R) = Rate per annum
- (T) = Time in years
Amount Under Simple Interest
[
A=P+SI
]
Finding Principal
[
P=
\frac{SI\times100}{R\times T}
]
Finding Rate
[
R=
\frac{SI\times100}{P\times T}
]
Finding Time
[
T=
\frac{SI\times100}{P\times R}
]
Important Compound Interest Formulas
For annual compounding:
[
A=
P\left(1+\frac{R}{100}\right)^T
]
Then:
[
CI=A-P
]
where:
- (P) = Principal
- (R) = Annual rate of interest
- (T) = Number of years
- (A) = Amount
- (CI) = Compound Interest
Understanding Compound Interest
Suppose ₹10,000 is invested at 10% compound interest.
End of Year 1
Interest:
[
10%\text{ of }10000=1000
]
Amount:
[
11000
]
End of Year 2
Interest is now calculated on ₹11,000:
[
10%\text{ of }11000=1100
]
Final amount:
[
12100
]
Total compound interest:
[
12100-10000=2100
]
This extra ₹100 compared with simple interest arises because interest is earned on the previous interest.
Simple Interest vs Compound Interest
| Simple Interest | Compound Interest |
|---|---|
| Interest is calculated on original principal | Interest can be calculated on accumulated amount |
| Interest per year remains constant when rate is fixed | Interest amount can increase over time |
| Easier to calculate | Uses compounding |
| Growth is linear | Growth is multiplicative |
For short periods and low rates, the difference may be small.
Over longer periods, compounding can create a much larger difference.
Difference Between SI and CI for Two Years
For two years at the same annual rate:
[
CI-SI
P\left(\frac{R}{100}\right)^2
]
For example:
Principal:
₹10,000
Rate:
10%
Difference:
[
10000\left(\frac{10}{100}\right)^2
]
[
=100
]
This shortcut is useful in aptitude tests.
A Common Interest Mistake
Do not calculate compound interest as:
[
\frac{P\times R\times T}{100}
]
That formula calculates Simple Interest.
For compound interest, the amount changes as interest is added to the principal.
For annual compounding:
[
A=P\left(1+\frac{R}{100}\right)^T
]
Then subtract the original principal:
[
CI=A-P
]
Another Common Mistake: Confusing Interest and Amount
Suppose:
Principal = ₹10,000
Compound amount after two years = ₹12,100.
The compound interest is not ₹12,100.
It is:
[
12100-10000
]
[
=2100
]
Therefore:
Amount = Principal + Interest
Topics Covered in This Test
This Simple and Compound Interest test covered:
- Simple Interest
- Principal
- Rate of interest
- Time
- Amount
- Compound Interest
- Annual compounding
- Finding principal from amount
- Finding rate
- Finding time
- Difference between SI and CI
- Comparing investment schemes
- Doubling under simple interest
- Multi-step interest calculations
Understanding these concepts is also useful in commercial arithmetic, banking aptitude, investments, loans, percentages, and financial mathematics.
Frequently Asked Questions
What is Simple Interest?
Simple Interest is interest calculated only on the original principal for the entire investment or loan period.
The formula is:
[
SI=\frac{PRT}{100}
]
What is Compound Interest?
Compound Interest is calculated on the accumulated amount, so previous interest can also earn interest in subsequent periods.
What is Principal?
Principal is the original amount invested or borrowed.
What is Amount?
Amount is the total value after adding interest to the principal.
For simple interest:
[
A=P+SI
]
For compound interest:
[
A=P+CI
]
What is the main difference between Simple and Compound Interest?
Under Simple Interest, interest is calculated on the original principal.
Under Compound Interest, interest may be calculated on the accumulated amount containing both principal and previous interest.
Is Compound Interest always greater than Simple Interest?
For the same positive principal, positive rate, and a period longer than one compounding interval, compound interest is generally greater than simple interest when both are compared under equivalent annual conditions.
For one year with annual compounding, they are equal.
How do I calculate compound amount for two years?
Use:
[
A=
P\left(1+\frac{R}{100}\right)^2
]
Are Simple and Compound Interest questions important for placement tests?
Yes. They are common quantitative aptitude topics and also strengthen understanding of percentages and commercial arithmetic.
Which topic should I understand before learning interest?
A good understanding of Percentages makes both Simple Interest and Compound Interest much easier.
Conclusion
Simple and Compound Interest questions become easier when you first identify four quantities:
Principal → Rate → Time → Interest/Amount
For Simple Interest, the original principal remains the basis of the interest calculation.
For Compound Interest, the accumulated amount can become the basis for the next period’s interest.
The most important formulas are:
[
SI=\frac{PRT}{100}
]
and:
[
A=P\left(1+\frac{R}{100}\right)^T
]
Once these relationships are clear, questions involving missing principal, rate, time, and comparisons between investment schemes can be solved systematically.
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