August 17, 2026

20 Problems on Ages Aptitude Questions with Answers and Solutions

20 Problems on Ages Aptitude Questions with Answers and Solutions

Problems on Ages is a common quantitative aptitude topic in placement tests, competitive examinations, recruitment assessments, and entrance tests. These questions test your ability to form and solve equations based on present ages, past ages, future ages, age ratios, and differences between ages.

This practice set contains 20 original Problems on Ages aptitude questions with detailed answers and step-by-step solutions. The questions begin with basic present-age calculations and gradually move toward ratio-based and multi-person age problems.

📚 Want to practice more aptitude topics? Visit our [Free Aptitude Tests and MCQs for Placements, Competitive Exams and Interview Preparation] page for topic-wise tests covering Quantitative Aptitude, Logical Reasoning, Verbal Ability, Computer Aptitude, Data Interpretation, and placement preparation.

Try to solve all 20 questions before checking the answers.

Detailed answers and solutions are provided after Question 20.

Problems on Ages Aptitude Test

Question 1

Juhi is 6 years older than Cherry. If Cherry is 18 years old, what is Juhi’s age?

A. 22 years
B. 23 years
C. 24 years
D. 25 years

Question 2

The present ages of Charlie and Kanchan are in the ratio 3 : 5. If Charlie is 21 years old, what is Kanchan’s age?

A. 30 years
B. 32 years
C. 35 years
D. 38 years

Question 3

The sum of the present ages of Juhi and Nyra is 44 years. If Juhi is 8 years older than Nyra, what is Nyra’s age?

A. 16 years
B. 18 years
C. 20 years
D. 22 years

Question 4

Kanchan is three times as old as Cherry. If the sum of their ages is 48 years, what is Cherry’s age?

A. 10 years
B. 12 years
C. 14 years
D. 16 years

Question 5

Five years ago, Charlie was 18 years old. What will his age be 7 years from now?

A. 28 years
B. 29 years
C. 30 years
D. 31 years

Question 6

The present ages of Juhi and Cherry are in the ratio 4 : 3. After 6 years, their ages will be in the ratio 5 : 4. What is Juhi’s present age?

A. 20 years
B. 22 years
C. 24 years
D. 26 years

Question 7

A mother is 26 years older than her daughter. After 4 years, the mother’s age will be twice the daughter’s age. What is the daughter’s present age?

A. 18 years
B. 20 years
C. 22 years
D. 24 years

Question 8

The present ages of Kanchan and Nyra are in the ratio 7 : 4. If the difference between their ages is 18 years, what is Nyra’s age?

A. 20 years
B. 22 years
C. 24 years
D. 26 years

Question 9

Ten years ago, Juhi was twice as old as Cherry. At present, Juhi is 40 years old. What is Cherry’s present age?

A. 22 years
B. 24 years
C. 25 years
D. 30 years

Question 10

The average age of 5 friends is 24 years. If four of them are aged 20, 22, 25, and 27 years, what is the age of the fifth friend?

A. 24 years
B. 25 years
C. 26 years
D. 27 years

Question 11

A father is 4 times as old as his son. After 12 years, he will be twice as old as his son. What is the son’s present age?

A. 6 years
B. 8 years
C. 10 years
D. 12 years

Question 12

The present ages of Juhi and Charlie are in the ratio 5 : 7. Six years ago, their ages were in the ratio 2 : 3. What is Juhi’s present age?

A. 25 years
B. 30 years
C. 35 years
D. 40 years

Question 13

The sum of the ages of Cherry and Nyra is 50 years. Five years ago, Cherry was twice as old as Nyra. What is Nyra’s present age?

A. 18 years
B. 20 years
C. 22 years
D. 24 years

Question 14

Kanchan’s present age is 40 years. After how many years will her age be ( \frac{5}{4} ) of her present age?

A. 8 years
B. 10 years
C. 12 years
D. 15 years

Question 15

The present ages of Juhi, Cherry, and Charlie are in the ratio 2 : 3 : 5. If their total age is 80 years, what is Charlie’s age?

A. 32 years
B. 36 years
C. 40 years
D. 44 years

Question 16

A father and son together are 66 years old. Six years ago, the father was 4 times as old as the son. What is the son’s present age?

A. 16 years
B. 18 years
C. 20 years
D. 22 years

Question 17

The present ages of Juhi and Nyra are in the ratio 6 : 5. Four years from now, the ratio of their ages will be 7 : 6. What is Nyra’s present age?

A. 16 years
B. 18 years
C. 20 years
D. 24 years

Question 18

A person’s age 8 years ago was ( \frac{2}{3} ) of their present age. What is the person’s present age?

A. 20 years
B. 22 years
C. 24 years
D. 28 years

Question 19

Juhi is 12 years older than Cherry. Five years from now, Juhi will be ( \frac{3}{2} ) times Cherry’s age. What is Cherry’s present age?

A. 17 years
B. 19 years
C. 21 years
D. 23 years

Question 20

The present ages of a mother and daughter are in the ratio 8 : 3. After 10 years, their ages will be in the ratio 3 : 2. What is the daughter’s present age?

A. 4 years
B. 5 years
C. 6 years
D. 8 years

Answers and Detailed Solutions

Answer 1: C — 24 years

Cherry’s age:

[
18
]

Juhi is 6 years older.

Therefore:

[
18+6=24
]

Correct Answer: 24 years

Answer 2: C — 35 years

Given ratio:

[
Charlie:Kanchan=3:5
]

Charlie is 21 years old.

Therefore:

[
3\text{ parts}=21
]

One part:

[
21\div3=7
]

Kanchan’s age:

[
5\times7=35
]

Therefore:

Correct Answer: 35 years

Answer 3: B — 18 years

Let Nyra’s age be:

[
x
]

Juhi is 8 years older:

[
x+8
]

Their total age is 44.

Therefore:

[
x+(x+8)=44
]

[
2x+8=44
]

[
2x=36
]

[
x=18
]

Therefore:

Nyra’s age = 18 years

Answer 4: B — 12 years

Let Cherry’s age be:

[
x
]

Kanchan’s age:

[
3x
]

Their sum is 48:

[
x+3x=48
]

[
4x=48
]

[
x=12
]

Therefore:

Correct Answer: 12 years

Answer 5: C — 30 years

Five years ago, Charlie was 18.

Therefore, his present age is:

[
18+5=23
]

Seven years from now:

[
23+7=30
]

Therefore:

Correct Answer: 30 years

Answer 6: C — 24 years

Present age ratio:

[
Juhi:Cherry=4:3
]

Let their present ages be:

[
4x \text{ and } 3x
]

After 6 years:

[
\frac{4x+6}{3x+6}=\frac{5}{4}
]

Cross multiply:

[
4(4x+6)=5(3x+6)
]

[
16x+24=15x+30
]

[
x=6
]

Juhi’s present age:

[
4\times6=24
]

Therefore:

Correct Answer: 24 years

Answer 7: C — 22 years

Let the daughter’s present age be:

[
x
]

Mother’s present age:

[
x+26
]

After 4 years:

Daughter:

[
x+4
]

Mother:

[
x+30
]

According to the question:

[
x+30=2(x+4)
]

[
x+30=2x+8
]

[
x=22
]

Therefore:

Correct Answer: 22 years

Answer 8: C — 24 years

Present age ratio:

[
Kanchan:Nyra=7:4
]

Difference in ratio parts:

[
7-4=3
]

Actual difference:

18 years.

Therefore:

[
3\text{ parts}=18
]

One part:

[
18\div3=6
]

Nyra’s age:

[
4\times6=24
]

Therefore:

Correct Answer: 24 years

Answer 9: C — 25 years

Juhi’s present age:

40 years.

Ten years ago:

[
40-10=30
]

At that time, Juhi was twice Cherry’s age.

Therefore Cherry’s age 10 years ago:

[
30\div2=15
]

Cherry’s present age:

[
15+10=25
]

Therefore:

Correct Answer: 25 years

Answer 10: C — 26 years

Average age:

24 years

Number of friends:

5

Total age:

[
24\times5=120
]

Sum of four known ages:

[
20+22+25+27=94
]

Fifth friend’s age:

[
120-94=26
]

Therefore:

Correct Answer: 26 years

Answer 11: A — 6 years

Let the son’s present age be:

[
x
]

Father’s present age:

[
4x
]

After 12 years:

Son:

[
x+12
]

Father:

[
4x+12
]

According to the question:

[
4x+12=2(x+12)
]

[
4x+12=2x+24
]

[
2x=12
]

[
x=6
]

Therefore:

Correct Answer: 6 years

Answer 12: B — 30 years

Present ratio:

[
Juhi:Charlie=5:7
]

Let their present ages be:

[
5x \text{ and } 7x
]

Six years ago:

[
\frac{5x-6}{7x-6}=\frac{2}{3}
]

Cross multiply:

[
3(5x-6)=2(7x-6)
]

[
15x-18=14x-12
]

[
x=6
]

Juhi’s present age:

[
5\times6=30
]

Therefore:

Correct Answer: 30 years

Answer 13: B — 20 years

Let Nyra’s present age be:

[
x
]

Cherry’s present age:

[
50-x
]

Five years ago:

Nyra:

[
x-5
]

Cherry:

[
45-x
]

According to the question:

[
45-x=2(x-5)
]

[
45-x=2x-10
]

[
55=3x
]

[
x=\frac{55}{3}
]

This is approximately:

[
18.33
]

So the original values do not produce a clean integer answer. To keep the MCQ precise, use the corrected question:

The sum of the ages of Cherry and Nyra is 55 years. Five years ago, Cherry was twice as old as Nyra. What is Nyra’s present age?

Then:

[
50-x=2(x-5)
]

[
50-x=2x-10
]

[
60=3x
]

[
x=20
]

Therefore, with the corrected total of 55 years:

Correct Answer: 20 years

Answer 14: B — 10 years

Kanchan’s present age:

[
40
]

Future age required:

[
\frac{5}{4}\times40
]

[
=50
]

Years required:

[
50-40=10
]

Therefore:

Correct Answer: 10 years

Answer 15: C — 40 years

Age ratio:

[
2:3:5
]

Total parts:

[
2+3+5=10
]

Total age:

80 years.

One part:

[
80\div10=8
]

Charlie’s age represents 5 parts:

[
5\times8=40
]

Therefore:

Correct Answer: 40 years

Answer 16: B — 18 years

Let the son’s present age be:

[
x
]

Father’s present age:

[
66-x
]

Six years ago:

Son:

[
x-6
]

Father:

[
60-x
]

According to the question:

[
60-x=4(x-6)
]

[
60-x=4x-24
]

[
84=5x
]

[
x=16.8
]

This does not match the options exactly.

For a clean aptitude question, change the total present age from 66 years to 72 years.

Then:

Father’s present age:

[
72-x
]

Six years ago:

[
66-x=4(x-6)
]

[
66-x=4x-24
]

[
90=5x
]

[
x=18
]

Therefore, with the corrected total of 72 years:

Correct Answer: 18 years

Answer 17: C — 20 years

Present ratio:

[
Juhi:Nyra=6:5
]

Let present ages be:

[
6x \text{ and } 5x
]

After 4 years:

[
\frac{6x+4}{5x+4}=\frac{7}{6}
]

Cross multiply:

[
6(6x+4)=7(5x+4)
]

[
36x+24=35x+28
]

[
x=4
]

Nyra’s present age:

[
5\times4=20
]

Therefore:

Correct Answer: 20 years

Answer 18: C — 24 years

Let present age be:

[
x
]

Eight years ago:

[
x-8
]

According to the question:

[
x-8=\frac{2}{3}x
]

Multiply by 3:

[
3x-24=2x
]

Therefore:

[
x=24
]

Correct Answer: 24 years

Answer 19: B — 19 years

Let Cherry’s present age be:

[
x
]

Juhi’s present age:

[
x+12
]

Five years from now:

Cherry:

[
x+5
]

Juhi:

[
x+17
]

According to the question:

[
x+17=\frac{3}{2}(x+5)
]

Multiply by 2:

[
2x+34=3x+15
]

[
x=19
]

Therefore:

Correct Answer: 19 years

Answer 20: C — 6 years

Present ratio:

[
Mother:Daughter=8:3
]

Let present ages be:

[
8x \text{ and } 3x
]

After 10 years:

[
\frac{8x+10}{3x+10}=\frac{3}{2}
]

Cross multiply:

[
2(8x+10)=3(3x+10)
]

[
16x+20=9x+30
]

[
7x=10
]

[
x=\frac{10}{7}
]

This does not produce the listed answer.

For a clean integer-based aptitude question, revise the future period to 12 years and ratio to 2 : 1:

The present ages of a mother and daughter are in the ratio 8 : 3. After 12 years, their ages will be in the ratio 2 : 1. What is the daughter’s present age?

Then:

[
\frac{8x+12}{3x+12}=2
]

[
8x+12=6x+24
]

[
2x=12
]

[
x=6
]

Daughter’s age:

[
3x=18
]

That gives 18, so this also changes the options substantially.

A better corrected version is:

The present ages of a mother and daughter are in the ratio 7 : 2. After 10 years, their ages will be in the ratio 3 : 1. What is the daughter’s present age?

Let ages be:

[
7x,\ 2x
]

After 10 years:

[
\frac{7x+10}{2x+10}=3
]

[
7x+10=6x+30
]

[
x=20
]

Daughter’s age:

[
2x=40
]

Again too large.

For publication, I recommend replacing Question 20 completely with this clean version:

Corrected Question 20

The present ages of a mother and daughter are in the ratio 5 : 2. After 8 years, their ages will be in the ratio 2 : 1. What is the daughter’s present age?

A. 12 years
B. 14 years
C. 16 years
D. 18 years

Let ages be:

[
5x,\ 2x
]

After 8 years:

[
\frac{5x+8}{2x+8}=2
]

[
5x+8=4x+16
]

[
x=8
]

Daughter’s present age:

[
2x=16
]

Therefore:

Correct Answer: C — 16 years

Quick Answer Key

QuestionAnswerQuestionAnswer
1C11A
2C12B
3B13B*
4B14B
5C15C
6C16B*
7C17C
8C18C
9C19B
10C20C*

*Use the corrected versions of Questions 13, 16, and 20 given in the solutions before publishing.

How Did You Score?

Correct AnswersPerformance
18–20Excellent — You have a strong understanding of age problems.
15–17Very Good — Your fundamentals are strong; practice ratio-based and past/future age problems.
11–14Good — Review equation formation and age-ratio questions.
6–10Needs Practice — Revise basic present, past, and future age relationships.
0–5Beginner — Start with age differences and simple ratio questions before attempting advanced problems.

Important Concepts for Problems on Ages

Present Age

If a person’s present age is:

[
x
]

then:

After (n) years

[
x+n
]

(n) years ago

[
x-n
]

This simple relationship is the foundation of most age problems.

Difference Between Ages Remains Constant

Suppose Juhi is 8 years older than Cherry today.

After 10 years, Juhi will still be:

8 years older

Ten years ago, Juhi was also:

8 years older

The numerical difference between two people’s ages does not change with time.

Age Ratios Do Change

Although the age difference remains constant, the ratio of ages changes over time.

For example:

Present ages:

20 and 10

Ratio:

[
2:1
]

Ten years later:

30 and 20

Ratio:

[
3:2
]

Therefore, do not assume that an age ratio remains constant.

Solving Ratio-Based Age Problems

Suppose present ages are in the ratio:

[
3:5
]

Represent them as:

[
3x \text{ and } 5x
]

If their total age is 48:

[
3x+5x=48
]

[
8x=48
]

[
x=6
]

Therefore:

[
3x=18
]

and:

[
5x=30
]

Past-Age Problems

Suppose Juhi’s present age is:

[
x
]

Five years ago:

[
x-5
]

If Cherry’s present age is:

[
y
]

five years ago:

[
y-5
]

Then create an equation using the relationship given for that earlier time.

Future-Age Problems

Suppose the present ages are:

[
x \text{ and } y
]

Eight years from now:

[
x+8
]

and:

[
y+8
]

Use these future ages when constructing the required ratio or equation.

Average Age

Average-age questions use the same formula as ordinary average problems:

[
\text{Average Age}

\frac{\text{Total Age}}
{\text{Number of People}}
]

Therefore:

[
\text{Total Age}

\text{Average Age}\times\text{Number of People}
]

This is useful when one person’s age is unknown.

A Common Age Problem Mistake

Suppose two present ages are:

[
4x \text{ and } 5x
]

Five years later, the ages become:

[
4x+5
]

and:

[
5x+5
]

They do not become:

[
4(x+5)
]

and:

[
5(x+5)
]

because the same number of years is added to each person’s actual age, not to the ratio multiplier.

Another Common Mistake: Changing the Age Difference

Suppose the age difference between two people is 20 years.

That difference remains 20 years:

  • today,
  • 5 years ago,
  • 10 years later.

Only their ratio changes.

This observation can often simplify age problems considerably.

Topics Covered in This Test

This Problems on Ages aptitude test covered:

  • Present ages
  • Past ages
  • Future ages
  • Age differences
  • Age ratios
  • Sum of ages
  • Average age
  • Parent-child age problems
  • Ratio changes over time
  • Forming equations
  • Three-person age ratios
  • Fraction-based age relationships

These questions strengthen your ability to translate verbal information into mathematical equations.

Frequently Asked Questions

What are Problems on Ages in aptitude?

Problems on Ages are mathematical questions involving the present, past, or future ages of one or more people.

What is the most important rule in age problems?

If a person’s present age is (x), then:

After (n) years:

[
x+n
]

and (n) years ago:

[
x-n
]

Does the age difference between two people change?

No.

The difference between their ages always remains constant.

Does the ratio of two people’s ages remain constant?

No.

The ratio usually changes as both people grow older.

How should I represent ages given in a ratio?

If the ratio is:

[
3:5
]

represent the ages as:

[
3x \text{ and } 5x
]

Then use the additional information to determine (x).

How do I solve parent-child age problems?

Represent the child’s age with a variable and express the parent’s age using the given difference, ratio, or multiple.

Then form an equation using the age relationship at the specified time.

Are age questions important for placement tests?

Yes. Problems on Ages are commonly included in quantitative aptitude because they test algebraic reasoning, ratios, and equation formation.

Which topics help with age problems?

A good understanding of:

  • ratios,
  • averages,
  • linear equations, and
  • basic arithmetic

makes age problems much easier.

Conclusion

Problems on Ages become straightforward once you translate each statement into an algebraic relationship.

The most useful facts are:

Present age = (x)

Age after (n) years = (x+n)

Age (n) years ago = (x-n)

and:

The difference between two people’s ages remains constant.

For ratio questions, represent the ages using multiples such as:

[
3x,\ 5x
]

and then form an equation using the information provided.

With regular practice, even complicated age questions involving several people and different time periods can be solved systematically.

📚 Continue your aptitude preparation: Return to [Free Aptitude Tests and MCQs for Placements, Competitive Exams and Interview Preparation] to explore all available tests in Quantitative Aptitude, Logical Reasoning, Verbal Ability, Computer Aptitude, Data Interpretation, and Placement Preparation.

Previous Test:
20 Simple and Compound Interest Questions with Answers and Solutions

This completes today’s initial Quantitative Aptitude practice series.

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